Can a variable number of arguments be passed to a function?

Question

In a similar way to using varargs in C or C++:

fn(a, b)
fn(a, b, c, d, ...)

Answer 1

Another way to go about it, besides the nice answers already mentioned, depends upon the fact that you can pass optional named arguments by position. For example,

def f(x,y=None):
    print(x)
    if y is not None:
        print(y)

Yields

In [11]: f(1,2)
1
2

In [12]: f(1)
1