urllib2 file name

Question

If I open a file using urllib2, like so:

remotefile = urllib2.urlopen(\'http://example.com/somefile.zip\')

Is there an easy way to get the

Answer 1

not that I know of.

but you can parse it easy enough like this:

url = 'http://example.com/somefile.zip'
print url.split('/')[-1]