urllib2 file name

Question

If I open a file using urllib2, like so:

remotefile = urllib2.urlopen(\'http://example.com/somefile.zip\')

Is there an easy way to get the

Answer 1

The os.path.basename function works not only for file paths, but also for urls, so you don't have to manually parse the URL yourself. Also, it's important to note that you should use result.url instead of the original url in order to follow redirect responses:

import os
import urllib2
result = urllib2.urlopen(url)
real_url = urllib2.urlparse.urlparse(result.url)
filename = os.path.basename(real_url.path)