How to convert a command-line argument to int?

Question

I need to get an argument and convert it to an int. Here is my code so far:

#include 


using namespace std;
int main(int argc,int argvx[]) {         


        

Answer 1

Note that your main arguments are not correct. The standard form should be:

int main(int argc, char *argv[])

or equivalently:

int main(int argc, char **argv)

There are many ways to achieve the conversion. This is one approach:

#include 

int main(int argc, char *argv[])
{
    if (argc >= 2)
    {
        std::istringstream iss( argv[1] );
        int val;

        if (iss >> val)
        {
            // Conversion successful
        }
    }

    return 0;
}