Implicit type conversion rules in C++ operators

Question

I want to be better about knowing when I should cast. What are the implicit type conversion rules in C++ when adding, multiplying, etc. For example,

int + fl         


        

Answer 1

Arithmetic operations involving float results in float.

int + float = float
int * float = float
float * int = float
int / float = float
float / int = float
int / int = int

For more detail answer. Look at what the section §5/9 from the C++ Standard says

Many binary operators that expect operands of arithmetic or enumeration type cause conversions and yield result types in a similar way. The purpose is to yield a common type, which is also the type of the result.

This pattern is called the usual arithmetic conversions, which are defined as follows:

— If either operand is of type long double, the other shall be converted to long double.

— Otherwise, if either operand is double, the other shall be converted to double.

— Otherwise, if either operand is float, the other shall be converted to float.

— Otherwise, the integral promotions (4.5) shall be performed on both operands.54)

— Then, if either operand is unsigned long the other shall be converted to unsigned long.

— Otherwise, if one operand is a long int and the other unsigned int, then if a long int can represent all the values of an unsigned int, the unsigned int shall be converted to a long int; otherwise both operands shall be converted to unsigned long int.

— Otherwise, if either operand is long, the other shall be converted to long.

— Otherwise, if either operand is unsigned, the other shall be converted to unsigned.

[Note: otherwise, the only remaining case is that both operands are int ]