Python: 'break' outside loop

Question

in the following python code:

narg=len(sys.argv)
print \"@length arg= \", narg
if narg == 1:
        print \"@Usage: input_filename nelements nintervals\"
           


        

Answer 1

Because the break statement is intended to break out of loops. You don't need to break out of an if statement - it just ends at the end.