Accessing value returned by scala futures

Question

I am a newbie to scala futures and I have a doubt regarding the return value of scala futures.

So, generally syntax for a scala future is

 def downl         


        

Answer 1

You can do something like that. If The wait time that is given in Await.result method is less than it takes the awaitable to execute, you will have a TimeoutException, and you need to handle the error (or any other error).

import scala.concurrent._
import ExecutionContext.Implicits.global
import scala.util.{Try, Success, Failure}
import scala.concurrent.duration._

object MyObject {
    def main(args: Array[String]) {

        val myVal: Future[String] = Future { silly() }

        // values less than 5 seconds will go to 
        // Failure case, because silly() will not be done yet
        Try(Await.result(myVal, 10 seconds)) match {
            case Success(extractedVal) => { println("Success Happened: " + extractedVal) }
            case Failure(_) => { println("Failure Happened") }
            case _ => { println("Very Strange") }
        }      
    }

    def silly(): String = {
        Thread.sleep(5000)
        "Hello from silly"
        }
}