Iterate over pairs in a list (circular fashion) in Python

Question

The problem is easy, I want to iterate over each element of the list and the next one in pairs (wrapping the last one with the first).

I\'ve thought about two unpyth

Answer 1

def pairs(ex_list):
    for i, v in enumerate(ex_list):
        if i < len(list) - 1:
            print v, ex_list[i+1]
        else:
            print v, ex_list[0]

Enumerate returns a tuple with the index number and the value. I print the value and the following element of the list ex_list[i+1]. The if i < len(list) - 1 means if v is not the last member of the list. If it is: print v and the first element of the list print v, ex_list[0].

Edit:

You can make it return a list. Just append the printed tuples to a list and return it.

def pairs(ex_list):
    result = []
    for i, v in enumerate(ex_list):
        if i < len(list) - 1:
            result.append((v, ex_list[i+1]))
        else:
            result.append((v, ex_list[0]))
    return result