Iterate over pairs in a list (circular fashion) in Python

Question

The problem is easy, I want to iterate over each element of the list and the next one in pairs (wrapping the last one with the first).

I\'ve thought about two unpyth

Answer 1

Even shorter version of Fortran's zip * range solution (with lambda this time;):

group = lambda t, n: zip(*[t[i::n] for i in range(n)])

group([1, 2, 3, 3], 2)

gives:

[(1, 2), (3, 4)]