I have a directory with jpgs and other files in it.
[...]
['0.jpg', '1.jpg', '10.jpg', '11.jpg', '12.jpg', '13.jpg', '14.jpg',
'15.jpg', '16.jpg', '17.jpg', '18.jpg', '19.jpg', '2.jpg', '20.jpg',
'21.jpg', '22.jpg', '23.jpg', '24.jpg', '25.jpg', '26.jpg', '27.jpg',
'28.jpg', '29.jpg', '3.jpg', '30.jpg', '31.jpg', '32.jpg', '33.jpg',
'34.jpg', '35.jpg', '36.jpg', '37.jpg', '4.jpg', '5.jpg', '6.jpg',
'7.jpg', '8.jpg', '9.jpg'] Clearly it sorts blindly the most
significant number first. I tried using sorted() as you can see hoping
that it would fix it but it makes no difference
You can use splitext to get the part without the extension and convert it to an int for the sorting. If the list is named 'l' and the sorted list is named 'lsorted' you can use:
lsorted = sorted(l,key=lambda x: int(os.path.splitext(x)[0]))
l here is the list of images. If you have a directory of images, simply obtain a list of these images by :
l = os.listdir('/path/to/directory/of/images')
Explanation: os.path.splitext on '10.jpg' returns ['10','.jpg'] so taking the int() of element zero will give you want you want as long as the filenames without the extention only contain strings that can be converted to integers with int(). Otherwise you will run into an Error.
