Switch statement in Swift

Question

I\'m learning syntax of Swift and wonder, why the following code isn\'t working as I expect it to:

for i in 1...100{

    switch (i){
    case 1:
        Int         


        

Answer 1

Here are the two ways I use switch statement for this kind of problems .

1>> Using where keyword

func printNumberType(number : Int){
    
    switch number {
    case number where number % 3 == 0 && number % 5 == 0 :
        print("foo bar")
    case number where number % 3 == 0 :
        print("foo")
    case number where number % 5 == 0 :
        print("bar")
    default :
        print("Number is not divisible by 3 and 5")
    }
}

2>> Using values combination

func printNumberByMultipleValues(number : Int){
    
    let combination = (number % 3,number % 5)
    
    switch combination {
    case (0,0):
        print("foo bar")
    case (0,_) :
        print("foo")
    case (_,0) :
        print("bar")
    default :
        print("Number is not divisible by 3 and 5")
    }
}

Here is closer example for multiple value type .

var printNumberByMultipleValues : (Int)->() = { number in
    
    let combination = (number % 3,number % 5)
    
    switch combination {
    case (0,0):
        print("foo bar")
    case (0,_) :
        print("foo")
    case (_,0) :
        print("bar")
    default :
        print("Number is not divisible by 3 and 5")
    }
}