Execute a shell function with timeout

Question

Why would this work

timeout 10s echo \"foo bar\" # foo bar

but this wouldn\'t

function echoFooBar {
  echo \"foo bar\"
}

e         


        

Answer 1

function foo(){
    for i in {1..100};
    do 
        echo $i;  
        sleep 1;
    done;
}

cat <( foo ) # Will work 
timeout 3 cat <( foo ) # Will Work 
timeout 3 cat <( foo ) | sort # Wont work, As sort will fail 
cat <( timeout 3 cat <( foo ) ) | sort -r # Will Work