Execute a shell function with timeout

Question

Why would this work

timeout 10s echo \"foo bar\" # foo bar

but this wouldn\'t

function echoFooBar {
  echo \"foo bar\"
}

e         


        

Answer 1

As Douglas Leeder said you need a separate process for timeout to signal to. Workaround by exporting function to subshells and running subshell manually.

export -f echoFooBar
timeout 10s bash -c echoFooBar