Django: get URL of current page, including parameters, in a template

Question

Is there a way to get the current page URL and all its parameters in a Django template?

For example, a templatetag that would print a full URL like /foo/bar?p

Answer 1

Django has a lot of built-in stuff, but if you don't explicit what do you want to use, it won't be used.

So, in MTV schema (Model, Template, View) the view receives a request and uses a template render to generate a response, passing on it a dictionary or all local variables (using the locals() function) of this view. Knowing this, we can insert the current url that came from the response, like this:

views.py:

from django.shortcuts import render

def page(request):
    currentUrl = request.get_full_path()
    return render(request, 'app/page.html', locals())

Then, in the template 'app/page.html' you just have to do the following to display the currentUrl variable that we just created and passed through via locals():

app/template/page.html:

{{ currentUrl }}