Get a file name from a path

Question

What is the simplest way to get the file name that from a path?

string filename = \"C:\\\\MyDirectory\\\\MyFile.bat\"

In this example, I s

Answer 1

The Simplest way in C++17 is:

use the #include and filename() for filename with extension and stem() without extension.

    #include 
    #include 
    namespace fs = std::filesystem;

    int main()
    {
        string filename = "C:\\MyDirectory\\MyFile.bat";

    std::cout << fs::path(filename).filename() << '\n'
        << fs::path(filename).stem() << '\n'
        << fs::path("/foo/bar.txt").filename() << '\n'
        << fs::path("/foo/bar.txt").stem() << '\n'
        << fs::path("/foo/.bar").filename() << '\n'
        << fs::path("/foo/bar/").filename() << '\n'
        << fs::path("/foo/.").filename() << '\n'
        << fs::path("/foo/..").filename() << '\n'
        << fs::path(".").filename() << '\n'
        << fs::path("..").filename() << '\n'
        << fs::path("/").filename() << '\n';
    }

output:

MyFile.bat
MyFile
"bar.txt"
".bar"
"."
"."
".."
"."
".."
"/"

Reference: cppreference