Getting the object out of a MemberExpression?

Question

So, lets say I have the following expression in C#:

Expression> expr = () => foo.Bar;

How do I pull out a refer

Answer 1

Thanks, staks - your example helped me a lot! So i'd like to contribute with some addition to the first case:

To extract values from methods, one should replace code:

// fetch the root object reference:
var constExpr = expr as ConstantExpression;
var objReference = constExpr.Value;

with code:

    var newExpression = expr as NewExpression;
    if (newExpression != null)
    {                
        return newExpression.Constructor.Invoke(newExpression.Arguments.Select(GetObjectValue).ToArray());
    }

    var methodCallExpr = expr as MethodCallExpression;
    if (methodCallExpr != null)
    {
        var value = methodCallExpr.Method.Invoke(methodCallExpr.Object == null
                                                                 ? null
                                                                 : GetObjectValue(methodCallExpr.Object),
methodCallExpr.Arguments.Select(GetObjectValue).ToArray());
                    return value;
    }

    // fetch the root object reference:
    var constExpr = expr as ConstantExpression;
    if (constExpr == null)
    {
         return null;
    }
    var objReference = constExpr.Value;
    // ... the rest remains unchanged

that way one could extract values from expressions like:

aInstane.MethodCall(anArgument1, anArgument2) or
AType.MethodCall(anArgument1, anArgument2) or
new AType().MethodCall(anArgument1, aInstane.MethodCall(anArgument2, anArgument3))