Selenium webdriver: How do I find ALL of an element's attributes?

Question

In the Python Selenium module, once I have a WebElement object I can get the value of any of its attributes with get_attribute():

f         


        

Answer 1

Here is my attempt at an answer. I do only tested it on the search box of google's homepage. I made use of @alecxe's answer above about 'outerHTML' Having obtained the html, I used a regular expression ([a-z]+-?[a-z]+_?)='?"? to match the attribute names. I think the regex would just have to be modified to match an increasing number of cases. But the essential name we need is "whatever is behind the equal sign."

Given a webElement

def get_web_element_attribute_names(web_element):
    """Get all attribute names of a web element"""
    # get element html
    html = web_element.get_attribute("outerHTML")
    # find all with regex
    pattern = """([a-z]+-?[a-z]+_?)='?"?"""
    return re.findall(pattern, html)

Test it on the below code

import re
from selenium import webdriver

driver = webdriver.Firefox()
google = driver.get("http://www.google.com")

driver.find_element_by_link_text("English").click()
search_element = driver.find_element_by_name("q")
get_web_element_attribute_names(search_element)

output:

['class', 'id', 'maxlength', 'name', 'autocomplete', 'title', 'value', 'aria-label', 'aria-haspopup', 'role', 'aria-autocomplete', 'style', 'dir', 'spellcheck', 'type']