String slugification in Python

Question

I am in search of the best way to \"slugify\" string what \"slug\" is, and my current solution is based on this recipe

I have changed it a little bit to:

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Answer 1

def slugify(value):
    """
    Converts to lowercase, removes non-word characters (alphanumerics and
    underscores) and converts spaces to hyphens. Also strips leading and
    trailing whitespace.
    """
    value = unicodedata.normalize('NFKD', value).encode('ascii', 'ignore').decode('ascii')
    value = re.sub('[^\w\s-]', '', value).strip().lower()
    return mark_safe(re.sub('[-\s]+', '-', value))
slugify = allow_lazy(slugify, six.text_type)

This is the slugify function present in django.utils.text This should suffice your requirement.