Implicit VS Explicit Conversion

Question

The C++ Standard Library by Nicolai M. Josuttis states:

There is a minor difference between

X x;
Y y(x) //explicit conversion

and

Answer 1

The first form is direct initialization. The second is copy initialization.

Copy initialization implicitly calls a converting constructor or conversion operator and then explicitly calls a copy constructor (the copy constructor call may be elided, but an accessibility check must still be performed).

Consider a third possibility, which is copy-initialization, but the conversion is explicit:

Y y = Y(x);

or

Y y = (Y)x;