How does this program work?

Question

#include 

int main() {
    float a = 1234.5f;
    printf(\"%d\\n\", a);
    return 0;
}

It displays a 0!! How is that

Answer 1

Since you tagged it with C++ as well, this code does the conversion as you probably expect:

#include 

int main() {
    float a = 1234.5f;
    std::cout << a << " " << (int)a << "\n";
    return 0;
}

Output:

1234.5 1234