What is the method-wrapper type in Python 3? If I define a class like so:
class Foo(object):
def __init__(self, val):
self.val = val
def __e
This is because 'unbound methods' don't exist in Python 3.
In Python 3000, the concept of unbound methods has been removed, and the expression "A.spam" returns a plain function object. It turned out that the restriction that the first argument had to be an instance of A was rarely helpful in diagnosing problems, and frequently an obstacle to advanced usages --- some have called it "duck typing self" which seems an appropriate name. (Source)
In Python 2.x, we had bound methods and unbound methods. A bound method was bound to an object, meaning that when it was called, it passed the object instance as the first variable (self, normally). An unbound method was one where the function was a method, but without a instance it belonged to - it would throw an error if something other than an object instance was passed in to the method.
Now, in 3.x, this has been changed. Instead of bound/unbound methods, when you request a method of an object, it returns the function object, but wrapped in a wrapper function that passes the instance variable in. This way there is no need to make a distinction between bound and unbound methods - bound methods are wrapped, unbound are not.
To clarify the difference:
2.x:
a = A()
f = A.method # f is an unbound method - you must pass an instance of `A` in to it as the first argument.
f = a.method # f is a bound method, bound to the instance `a`.
3.x:
a = A()
f = A.method # f is a function
f = a.method # f is a wrapped function with it's first argument filled with `a`.
a.method can be thought of as:
def method-wrapper():
A.method(a)
For more on this, check out Guido's blog - the history of Python.
Edit:
So, the reason this all applies is that, here, __ne__() has not been overridden - it's at a default state, which is an identity check, implemented in C (line 980ish). The wrapper is there to provide the method with the above functionality.