Why use !! when converting int to bool?

Question

What can be a reason for converting an integer to a boolean in this way?

bool booleanValue = !!integerValue;

instead of just

Answer 1

It is used because the C language (and some pre-standard C++ compilers too) didn't have the bool type, just int. So the ints were used to represent logical values: 0 was supposed to mean false, and everything else was true. The ! operator was returning 1 from 0 and 0 from everything else. Double ! was used to invert those, and it was there to make sure that the value is just 0 or 1 depending on its logical value.

In C++, since introducing a proper bool type, there's no need to do that anymore. But you cannot just update all legacy sources, and you shouldn't have to, due to backward compatibility of C with C++ (most of the time). But many people still do it, from the same reason: to remain their code backward-compatible with old compilers which still don't understand bools.

And this is the only real answer. Other answers are misleading.