Dynamically creating a proxy class

Question

I am trying to create a proxy class dynamically. I know there are some very good frameworks out there to do this but this is purely a pet project as a learning exercise so

Answer 1

Have a look at System.Runtime.Remoting.Proxies.RealProxy. You can use this to create an instance that appears to be the target type from the perspective of the caller. RealProxy.Invoke provides a point from which you can simply invoke the target method on the underlying type or perform additional processing before/after the call (logging, for example).

Here's an example of a proxy that logs to the console before/after each method invocation:

public class LoggingProxy : RealProxy
{
    private readonly T _instance;

    private LoggingProxy(T instance)
        : base(typeof(T))
    {
        _instance = instance;
    }

    public static T Create(T instance)
    {
        return (T)new LoggingProxy(instance).GetTransparentProxy();
    }

    public override IMessage Invoke(IMessage msg)
    {
        var methodCall = (IMethodCallMessage)msg;
        var method = (MethodInfo)methodCall.MethodBase;

        try
        {
            Console.WriteLine("Before invoke: " + method.Name);
            var result = method.Invoke(_instance, methodCall.InArgs);
            Console.WriteLine("After invoke: " + method.Name);
            return new ReturnMessage(result, null, 0, methodCall.LogicalCallContext, methodCall);
        }
        catch (Exception e)
        {
            Console.WriteLine("Exception: " + e);
            if (e is TargetInvocationException && e.InnerException != null)
            {
                return new ReturnMessage(e.InnerException, msg as IMethodCallMessage);
            }

            return new ReturnMessage(e, msg as IMethodCallMessage);
        }
    }
}

Here is how you would use it:

IMyInterface intf = LoggingProxy.Create(new MyClass());
intf.MyProcedure();

The output to console would then be:

Before invoke: MyProcedure
Hello World
After invoke: MyProcedure