What is the difference between the bridge pattern and the strategy pattern?

Question

I tried to read many articles on dofactory, wikipedia and many sites. I have no idea on differences between bridge pattern and the strategy pattern.

I know both of t

Answer 1

1. Strategy Pattern is used for Behavioural decisions, while Bridge Pattern is used for Structural decisions.

2. Brigde Pattern separats the abstract elements from the implementation details, while Strategy Pattern is concerned making algorithms more interchangeable.

Strategy Pattern in UML

Brigde Pattern in UML

Strategy Pattern in Swift:

protocol PrintStrategy {
   func print(_ string: String) -> String
}

class Printer {
   let strategy: PrintStrategy

   init(strategy: PrintStrategy) {
      self.strategy = strategy
    }

  func print(_ string: String) -> String {
     return self.strategy.print(string)
  }
}

class UpperCaseStrategy: PrintStrategy {
    internal func print(_ string: String) -> String {
        return string.uppercased()
    }
}

class LowerCaseStrategy: PrintStrategy {
    internal func print(_ string: String) -> String {
        return string.lowercased()
    }
}

var lower = Printer(strategy: LowerCaseStrategy())
lower.print("I love Software Patterns")

var upper = Printer(strategy: UpperCaseStrategy())
upper.print("I love Software Patterns")

Brigde Pattern in Swift:

protocol Appliance {
   func run()
}

protocol Switch {
   let appliance: Appliance {get set}
   func turnOn()
}

class RemoteControl: Switch {
   var appliance: Appliance

   init(appliance: Appliance) {
       self.appliance = appliance
   }

   internal func turnOn() {
      appliance.run()
   }
}

class TV: Appliance {
   internal func run() {
      print("TV is ON")
   }
}

class Stereo: Appliance {
   internal func run() {
      print("Stereo is ON")
   }
}

var tvRemote = RemoteControl.init(appliance: TV())
tvRemote.turnOn()

var stereoRemote = RemoteControl.init(appliance: Stereo())
stereoRemote.turnOn()