In Ruby, how does coerce() actually work?

Question

It is said that when we have a class Point and knows how to perform point * 3 like the following:

class Point
  def initialize(x,y)         


        

Answer 1

I find myself often writing code along this pattern when dealing with commutativity:

class Foo
  def initiate(some_state)
     #...
  end
  def /(n)
   # code that handles Foo/n
  end

  def *(n)
    # code that handles Foo * n 
  end

  def coerce(n)
      [ReverseFoo.new(some_state),n]
  end

end

class ReverseFoo < Foo
  def /(n)
    # code that handles n/Foo
  end
  # * commutes, and can be inherited from Foo
end