Lambda capture as const reference?

Question

Is it possible to capture by const reference in a lambda expression?

I want the assignment marked below to fail, for example:

#include 

        

Answer 1

Using a const will simply have the algorithm ampersand set the string to it's original value, In other words, the lambda won't really define itself as parameter of the function, though the surrounding scope will have an extra variable... Without defining it though, it wouldn't define the string as the typical [&, &best_string](string const s) Therefore, its most likely better if we just leave it at that, trying to capture the reference.