Zipping streams using JDK8 with lambda (java.util.stream.Streams.zip)

Question

In JDK 8 with lambda b93 there was a class java.util.stream.Streams.zip in b93 which could be used to zip streams (this is illustrated in the tutorial Exploring Java8 Lambda

Answer 1

This is great. I had to zip two streams into a Map with one stream being the key and other being the value

Stream streamA = Stream.of("A", "B", "C");
Stream streamB  = Stream.of("Apple", "Banana", "Carrot", "Doughnut");    
final Stream> s = StreamUtils.zip(streamA,
                    streamB,
                    (a, b) -> {
                        final Map.Entry entry = new AbstractMap.SimpleEntry(a, b);
                        return entry;
                    });

System.out.println(s.collect(Collectors.toMap(e -> e.getKey(), e -> e.getValue())));

Output: {A=Apple, B=Banana, C=Carrot}