How to explain C pointers (declaration vs. unary operators) to a beginner?

Question

I have had the recent pleasure to explain pointers to a C programming beginner and stumbled upon the following difficulty. It might not seem like an issue at all if you alre

Answer 1

Basically Pointer is not a array indication. Beginner easily thinks that pointer looks like array. most of string examples using the

"char *pstr" it's similar looks like

"char str[80]"

But, Important things , Pointer is treated as just integer in the lower level of compiler.

Let's look examples::

#include 
#include 

int main(int argc, char **argv, char **env)
{
    char str[] = "This is Pointer examples!"; // if we assume str[] is located in 0x80001000 address

    char *pstr0 = str;   // or this will be using with
    // or
    char *pstr1 = &str[0];

    unsigned int straddr = (unsigned int)pstr0;

    printf("Pointer examples: pstr0 = %08x\n", pstr0);
    printf("Pointer examples: &str[0] = %08x\n", &str[0]);
    printf("Pointer examples: str = %08x\n", str);
    printf("Pointer examples: straddr = %08x\n", straddr);
    printf("Pointer examples: str[0] = %c\n", str[0]);

    return 0;
}

Results will like this 0x2a6b7ed0 is address of str[]

~/work/test_c_code$ ./testptr
Pointer examples: pstr0 = 2a6b7ed0
Pointer examples: &str[0] = 2a6b7ed0
Pointer examples: str = 2a6b7ed0
Pointer examples: straddr = 2a6b7ed0
Pointer examples: str[0] = T

So, Basically, Keep in mind Pointer is some kind of Integer. presenting the Address.