get current url in twig template?

Question

I looked around for the code to get the current path in a Twig template (and not the full URL), i.e. I don\'t want http://www.sitename.com/page, I only need

Answer 1

It should be noted that if you have additional query parameters in your URL, which are not part of the configured route, the accepted answer will not include them in the current URL (path).

Why would you want extra parameters?

For example, if you have a list page with records that can be filtered by keyword and the page has pagination, most likely the query variables for "keyword" and "page" will not be in your route. But in your forward and back buttons for paging, you need the full current URL (that contains the keywords so the next page is still filtered). And you need to modify the page variable.

How to Merge In Extra Query Parameters

So you can get the current route, and merge in the extra variables (after modifying one or more of those extra variables). Note that you are merging in your own variables to the app.request.query.all, and then merging that array into the app.request.attributes.get('_route_params'). The path() method requires that you provide all the required parameters of the route, which is why you need to include the _route_params.

{{ path(app.request.attributes.get('_route'), app.request.attributes.get('_route_params')|merge(app.request.query.all|merge({'page': 2 }))) }}

That's really ugly, but if you are developing pagination, you will need to modify the page variable on each separate link, so you have to include the whole thing each time. Perhaps others have a better solution.