Print a list in reverse order with range()?

Question

How can you produce the following list with range() in Python?

[9, 8, 7, 6, 5, 4, 3, 2, 1, 0]

Answer 1

Use the 'range' built-in function. The signature is range(start, stop, step). This produces a sequence that yields numbers, starting with start, and ending if stop has been reached, excluding stop.

>>> range(9,-1,-1)   
    [9, 8, 7, 6, 5, 4, 3, 2, 1, 0]
>>> range(-2, 6, 2)
    [-2, 0, 2, 4]

In Python 3, this produces a non-list range object, which functions effectively like a read-only list (but uses way less memory, particularly for large ranges).