Need of serialization in Java [closed]

Answer 1

public class Serializer {

    public static void write(Object o, File f) throws IOException {
        f.delete();
        f.createNewFile();
        FileOutputStream fileOut = new FileOutputStream(f);
        ObjectOutputStream out = new ObjectOutputStream(fileOut);
        out.writeObject(o);
        out.close();
        fileOut.close();
    }

    public static Object read(File f) throws Exception{
        FileInputStream fileIn = new FileInputStream(f);
        ObjectInputStream in = new ObjectInputStream(fileIn);
        Object e = in.readObject();
        in.close();
        fileIn.close();
        return e;
    }

    public static byte[] toBytes(Object o) {
        byte[] bytes = null;
        ByteArrayOutputStream bos = new ByteArrayOutputStream();
        ObjectOutput out = null;
        try {
            out = new ObjectOutputStream(bos);
            out.writeObject(o);
            out.flush();
            bytes = bos.toByteArray();
        } catch (IOException e) {
            e.printStackTrace();
        } finally {
            try {
                bos.close();
            } catch (IOException ex) {
                // ignore close exception
            }
        }

        return bytes;
    }

    public static Object fromBytes(byte[] bytes) {
        Object o = null;
        ByteArrayInputStream bis = new ByteArrayInputStream(bytes);
        ObjectInput in = null;
        try {
            in = new ObjectInputStream(bis);
            o = in.readObject();
        } catch (IOException e) {
            e.printStackTrace();
        } catch (ClassNotFoundException e) {
            e.printStackTrace();
        } finally {
            try {
                if (in != null) {
                    in.close();
                }
            } catch (IOException ex) {
                // ignore close exception
            }
        }

        return o;
    }
}