How to determine if binary tree is balanced?

Question

It\'s been a while from those school years. Got a job as IT specialist at a hospital. Trying to move to do some actual programming now. I\'m working on binary trees now, a

Answer 1

Bonus exercise response. The simple solution. Obviously in a real implementation one might wrap this or something to avoid requiring the user to include height in their response.

IsHeightBalanced(tree, out height)
    if (tree is empty)
        height = 0
        return true
    balance = IsHeightBalanced(tree.left, heightleft) and IsHeightBalanced(tree.right, heightright)
    height = max(heightleft, heightright)+1
    return balance and abs(heightleft - heightright) <= 1