I have a data set with huge number of features, so analysing the correlation matrix has become very difficult. I want to plot a correlation matrix which we get using d
If your main goal is to visualize the correlation matrix, rather than creating a plot per se, the convenient pandas styling options is a viable built-in solution:
import pandas as pd
import numpy as np
rs = np.random.RandomState(0)
df = pd.DataFrame(rs.rand(10, 10))
corr = df.corr()
corr.style.background_gradient(cmap='coolwarm')
# 'RdBu_r' & 'BrBG' are other good diverging colormaps
Note that this needs to be in a backend that supports rendering HTML, such as the JupyterLab Notebook. (The automatic light text on dark backgrounds is from an existing PR and not the latest released version, pandas 0.23).
You can easily limit the digit precision:
corr.style.background_gradient(cmap='coolwarm').set_precision(2)
Or get rid of the digits altogether if you prefer the matrix without annotations:
corr.style.background_gradient(cmap='coolwarm').set_properties(**{'font-size': '0pt'})
The styling documentation also includes instructions of more advanced styles, such as how to change the display of the cell the mouse pointer is hovering over. To save the output you could return the HTML by appending the render() method and then write it to a file (or just take a screenshot for less formal purposes).
In my testing, style.background_gradient() was 4x faster than plt.matshow() and 120x faster than sns.heatmap() with a 10x10 matrix. Unfortunately it doesn't scale as well as plt.matshow(): the two take about the same time for a 100x100 matrix, and plt.matshow() is 10x faster for a 1000x1000 matrix.
There are a few possible ways to save the stylized dataframe:
render() method and then write the output to a file..xslx file with conditional formatting by appending the to_excel() method.By setting axis=None, it is now possible to compute the colors based on the entire matrix rather than per column or per row:
corr.style.background_gradient(cmap='coolwarm', axis=None)