Sizeof arrays and pointers

Question

Here is my sample code

#include
void main()
{
 int arr[]={1,2,3,4,5,6};
 char *ptr,a;
 a=\'c\';
 ptr=&a;
 int *ptr1,a1;
 a1=4;
 ptr1=&         


        

Answer 1

the sizeof() operator does not give you the number of elements in an array, it gives you the number of bytes a thing occupies in memory. Hence:

#include 

int main()
{
  char s[] = { 1, 2, 3, 4, 5, 0 };
  int xs[] = { 1, 2, 3, 4, 5, 0 };

  printf( "sizeof( s ) = %d\n",  sizeof( s  ) );
  printf( "sizeof( xs ) = %d\n", sizeof( xs ) );

  return 0;
}

sizeof( s ) = 6
sizeof( xs ) = 24