Java 8 Distinct by property

Question

In Java 8 how can I filter a collection using the Stream API by checking the distinctness of a property of each object?

For example I have a list of

Answer 1

Maybe will be useful for somebody. I had a little bit another requirement. Having list of objects A from 3rd party remove all which have same A.b field for same A.id (multiple A object with same A.id in list). Stream partition answer by Tagir Valeev inspired me to use custom Collector which returns Map>. Simple flatMap will do the rest.

 public static  Collector>> groupingDistinctBy(Function keyFunction, Function distinctFunction) {
    return groupingBy(keyFunction, Collector.of((Supplier>) HashMap::new,
            (map, error) -> map.putIfAbsent(distinctFunction.apply(error), error),
            (left, right) -> {
                left.putAll(right);
                return left;
            }, map -> new ArrayList<>(map.values()),
            Collector.Characteristics.UNORDERED)); }