This is more of a JavaScript Closure question than a Firebase question. In the following code, the Firebase callback isn\'t recognizing the variable myArr in the parent scop
The callback is recognizing/modifying myArr perfectly fine. The problem is that when your "doesn't work"-labeled console.log(myArr) executes, the callback hasn't fired yet.
Let's change your code a bit:
var myArr = [];
function show_fb() {
var firebase = new Firebase('https://scorching-fire-6816.firebaseio.com/');
firebase.on('child_added', on_post_added); // steps 1-3
console.log(myArr); // step 4
return myArr; // step 5
};
function on_post_added(snapshot) { // step 6
var newPost = snapshot.val();
myArr.push(newPost.user); // step 7
console.log(myArr); // step 8
}
Now it might be a bit easier to see what's going on.
child_added that will call on_post_added for every post that is added to your FirebaseHandling asynchronous code/callbacks like this takes some getting used to, but is crucial to working with Firebase or any other AJAX-like or event driven technology. Putting the callback's code into a separate function sometimes makes it a bit easier to see what's going on.
In the case of Firebase it may also help to realize that the event is called child_added for a reason. It is called whenever a child is added to the Firebase, not just when you first register your callback. So minutes later when some other client adds a child, your callback will still fire, adding a new child to myArr. At that stage the code in steps 4 and 5 above will long have executed and will not execute again.
The solution is simple: put anything that you want to do after a child is added into your callback:
var myArr = [];
function show_fb() {
var firebase = new Firebase('https://scorching-fire-6816.firebaseio.com/');
firebase.on('child_added', on_post_added);
};
function on_post_added(snapshot) {
var newPost = snapshot.val();
myArr.push(newPost.user);
console.log(myArr);
// do whatever else you need to do for a new post
}