Why is there an implicit type conversion from pointers to bool in C++?

Question

Consider the class foo with two constructors defined like this:

class foo
{
public:
    foo(const std::string& filename) {std::cout <<         


        

Answer 1

You're confusing two issues. One is that "blah" can be implicitly converted to a string and the other is that const char* can be implicitly converted into a boolean. It's very logical to see the compiler go to the implicit conversion which minimizes the total amount of conversions necessary.