No defined type of a function parameter defaults to int? Am I insane?

Question

For some odd reason I was copying an example in another language of which does not use types, and forgot to add one in to a function definition parameter, and it worked.

Answer 1

afaik this is called argument promotion. i do not recall the exact rules, but it comes down to the compiler being allowed to use int for arguments when he (she?) doesn't know the function prototype yet.