SQL SELECT to get the first N positive integers

Question

I need to get a result set containing the first N positive integers. Is it possible to use only standard SQL SELECT statement to get them (without any count table provided)?

Answer 1

Seems that what you want is a dummy rowset.

In MySQL, it's impossible without having a table.

Most major systems provide a way to do it:

• In Oracle:

  SELECT  level
  FROM    dual
  CONNECT BY
          level <= 10
  

• In SQL Server:

  WITH    q AS
          (
          SELECT  1 AS num
          UNION ALL
          SELECT  num + 1
          FROM    q
          WHERE   num < 10
          )
  SELECT  *
  FROM    q
  

• In PostgreSQL:

  SELECT  num
  FROM    generate_series(1, 10) num
  

MySQL lacks something like this and this is a serious drawback.

I wrote a simple script to generate test data for the sample tables in my blog posts, maybe it will be of use:

CREATE TABLE filler (
        id INT NOT NULL PRIMARY KEY AUTO_INCREMENT
) ENGINE=Memory;

CREATE PROCEDURE prc_filler(cnt INT)
BEGIN
        DECLARE _cnt INT;
        SET _cnt = 1;
        WHILE _cnt <= cnt DO
                INSERT
                INTO    filler
                SELECT  _cnt;
                SET _cnt = _cnt + 1;
        END WHILE;
END
$$

You call the procedure and the table gets filled with the numbers.

You can reuse it during the duration of the session.