Basic program to convert integer to Roman numerals?

Question

I\'m trying to write a code that converts a user-inputted integer into its Roman numeral equivalent. What I have so far is:

The point of the generate_

Answer 1

Another way to do this. separating out processing of number starting with 4 , 9 and others. it can be simplified further

def checkio(data):
romans = [("I",1),("V",5),("X",10),("L",50),("C",100),("D",500),("M",1000)]
romans_rev = list(sorted(romans,key = lambda x: -x[1]))
def process_9(num,roman_str):
    for (k,v) in romans:
        if (v > num):
            current_roman = romans[romans.index((k,v))]
            prev_roman = romans[romans.index((k,v)) - 2]
            roman_str += (prev_roman[0] + current_roman[0])
            num -= (current_roman[1] - prev_roman[1])
            break
    return num,roman_str
def process_4(num,roman_str):
    for (k,v) in romans:
        if (v > num):
            current_roman = romans[romans.index((k,v))]
            prev_roman = romans[romans.index((k,v)) - 1]
            roman_str += (prev_roman[0] + current_roman[0])
            num -= (current_roman[1] - prev_roman[1])
            break
    return num,roman_str
def process_other(num,roman_str):
    for (k,v) in romans_rev:
        div = num // v
        if ( div != 0 and num > 0 ):
            roman_str += k * div
            num -= v * div
            break
    return num,roman_str
def get_roman(num):
    final_roman_str = ""
    while (num > 0):
        if (str(num).startswith('4')):
            num,final_roman_str = process_4(num,final_roman_str)
        elif(str(num).startswith('9')):
            num,final_roman_str = process_9(num,final_roman_str)
        else:
            num,final_roman_str = process_other(num,final_roman_str)
    return final_roman_str

return get_roman(data)


print(checkio(number))