Why int j = 012 giving output 10?

Question

In my actual project It happened accidentally here is my modified small program.

I can\'t figure out why it is giving output 10?

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Answer 1

If a number is leading with 0, the number is interpreted as an octal number, not decimal. Octal values are base 8, decimal base 10.

System.out.println(012):
(2 * 8 ^ 0) + (1 * 8 ^ 1) = 10
12 = 2*8^0 + 1*8^1 ---> 10


System.out.println(0123)
(3 * 8 ^ 0) + (2 * 8 ^ 1) + (1 * 8 ^ 2) = 83
123 = 3*8^0 + 2*8^1 + 1*8^2 ---> 83