Destructor being called twice when being explicitly invoked

Question

I was experimenting with destructors in C++ with this piece of code:

#include 

struct temp
{
    ~temp() { std::cout << \"Hello!\" <         


        

Answer 1

You won't need to call to a destructor, although it is possible to do so. The compiler should implicitly run your destructor for you when an object is no longer used. When objects are created, your constructor is utilized for that object, if it has been declared with specific and initialized values for your class members. When you no longer need your object your destructor will run and delete member variable declarations and their values. This is most useful for languages that don't utilize automatic garbage collection, like C++.