Destructor being called twice when being explicitly invoked

Question

I was experimenting with destructors in C++ with this piece of code:

#include 

struct temp
{
    ~temp() { std::cout << \"Hello!\" <         


        

Answer 1

Calling the destructor does not free the object.

The destructor is there to clean up the internals of the object and then the object itsself is freed after the destructor finishes.

It's an error to do what you are doing similarly to the way that you can call delete twice on an object but it's an error to do so.

There are only a very few cases where you want to call the destructor manually and this isn't one of them. It's really there for the times you manually construct an object at a memory location using placement new and then need to be able to destruct it without freeing the memory.