I have a String array:
String[] str = {\"ab\" , \"fog\", \"dog\", \"car\", \"bed\"};
Arrays.sort(str);
System.out.println(Arrays.toString(str
Took my time to improve on the selected answer. This is more efficient
public static void customSort(final String order,String[] array){
String[] alphabets={"A","B","C","D","E","F","G","H","I","J","K","L","M","N","O","P","Q","R","S","T","U","V","W","X","Y","Z","0","1","2","3","4","5","6","7","8","9"};
String keyword=order;
for(int g=0; g() {
@Override
public int compare(String o1, String o2) {
int pos1 = 0;
int pos2 = 0;
for (int i = 0; i < Math.min(o1.length(), o2.length()) && pos1 == pos2; i++) {
pos1 = finalKeyword.toUpperCase().indexOf(o1.toUpperCase().charAt(i));
pos2 = finalKeyword.toUpperCase().indexOf(o2.toUpperCase().charAt(i));
}
if (pos1 == pos2 && o1.length() != o2.length()) {
return o1.length() - o2.length();
}
return pos1 - pos2 ;
}
});
//Arrays.sort(array, Collections.reverseOrder());
}