Short circuit on |= and &= assignment operators in C#

Question

I know that || and && are defined as short-circuit operators in C#, and such behaviour is guaranteed by the language specification, but do

Answer 1

No, the &= and |= operators are not doing short-circuit evaluation.

They are pseudo-operators, which the compiler converts into use of the & and | operators.

This code:

allEven &= IsEven(numbers[i]);

is exactly equivalent to:

allEven = allEven & IsEven(numbers[i]);

If you want the short circuited check, then you have to write it out using the short circuiting versions of the operators:

allEven = allEven && IsEven(numbers[i]);

There is no &&= pseudo operator, but the code above is exactly what the compiler would do if there was one.