Sorting list by an attribute that can be None

Question

I\'m trying to sort a list of objects using

my_list.sort(key=operator.attrgetter(attr_name))

but if any of the list items has attr = None

Answer 1

The solutions proposed here work, but this could be shortened further:

mylist.sort(key=lambda x: x or 0)

In essence, we can treat None as if it had value 0.

E.g.:

>>> mylist = [3, 1, None, None, 2, 0]
>>> mylist.sort(key=lambda x: x or 0)
>>> mylist
[None, None, 0, 1, 2, 3]