Hex to char array in C

Question

Given a string of hex values i.e. e.g. \"0011223344\" so that\'s 0x00, 0x11 etc.

How do I add these values to a char array?

Equivalent to say:

<

Answer 1

{
    char szVal[] = "268484927472";
    char szOutput[30];

    size_t nLen = strlen(szVal);
    // Make sure it is even.
    if ((nLen % 2) == 1)
    {
        printf("Error string must be even number of digits %s", szVal);
    }

    // Process each set of characters as a single character.
    nLen >>= 1;
    for (size_t idx = 0; idx < nLen; idx++)
    {
        char acTmp[3];
        sscanf(szVal + (idx << 1), "%2s", acTmp);
        szOutput[idx] = (char)strtol(acTmp, NULL, 16);
    }
}