How to pass whole Row to UDF - Spark DataFrame filter

Question

I\'m writing filter function for complex JSON dataset with lot\'s of inner structures. Passing individual columns is too cumbersome.

So I declared the following UDF

Answer 1

You have to use struct() function for constructing the row while making a call to the function, follow these steps.

Import Row,

import org.apache.spark.sql._

Define the UDF

def myFilterFunction(r:Row) = {r.get(0)==r.get(1)} 

Register the UDF

sqlContext.udf.register("myFilterFunction", myFilterFunction _)

Create the dataFrame

val records = sqlContext.createDataFrame(Seq(("sachin", "sachin"), ("aggarwal", "aggarwal1"))).toDF("text", "text2")

Use the UDF

records.filter(callUdf("myFilterFunction",struct($"text",$"text2"))).show

When u want all columns to be passed to UDF.

records.filter(callUdf("myFilterFunction",struct(records.columns.map(records(_)) : _*))).show 

Result:

+------+------+
|  text| text2|
+------+------+
|sachin|sachin|
+------+------+