Generating functions inside loop with lambda expression in python

Question

If I make two lists of functions:

def makeFun(i):
    return lambda: i

a = [makeFun(i) for i in range(10)]
b = [lambda: i for i in range(10)]

Answer 1

Nice catch. The lambda in the list comprehension is seeing the same local i every time.

You can rewrite it as:

a = []
for i in range(10):
    a.append(makefun(i))

b = []
for i in range(10):
    b.append(lambda: i)

with the same result.