How do you do *integer* exponentiation in C#?

Question

The built-in Math.Pow() function in .NET raises a double base to a double exponent and returns a double result.

W

Answer 1

For a short quick one-liner.

int pow(int i, int exp) => (exp == 0) ? 1 : i * pow(i, exp-1);

There are no negative exponent nor overflow checks.